(x/5)^2=2x

Solution for (x/5)^2=2x equation:

(x/5)^2=2x

We move all terms to the left:

(x/5)^2-(2x)=0

We add all the numbers together, and all the variables

(+x/5)^2-2x=0

We add all the numbers together, and all the variables

-2x+(+x/5)^2=0

We multiply all the terms by the denominator


-2x*5)^2+(+x=0

We add all the numbers together, and all the variables

x-2x*5)^2+(=0

Wy multiply elements

-10x^2+x=0

a = -10; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-10)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-10}=\frac{-2}{-20}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-10}=\frac{0}{-20}
=0
$